화학공정계산 3판 솔루션 RICHARD M.FELDER Elementary principles of chemical processes 솔루션

화학공정계산 3판 솔루션 RICHARD M.FELDER Elementary principles of chemical processes 솔루션

공정계산자료 (압축파일).zip

화학공정계산 3판 솔루션 RICHARD M.FELDER Elementary principles of chemical processes

화학공정계산 3판 솔루션 RICHARD M.FELDER - Elementary principles of chemical processes

화학화학공정계산 3판 솔루션 RICHARD M.FELDER - Elementary principles of chemical processes 3판 솔루션 RICHARD M.FELDER - Elementary principles of chemical processesCHAPTER TWO
2.1 (a)
= 18144 × 10 9 ms . 1 wk 1 d 1 h 1 s 38.1 ft / s 0.0006214 mi 3600 s (b) = 25.98 mi / h ⇒ 26.0 mi / h 3.2808 ft 1 h 3 wk 7d 24 h 3600 s 1000 ms

(c)

554 m 4 1d 1h d ? kg 24 h 60 min

1 kg 108 cm 4 = 3.85 × 10 4 cm 4 / min? g 1000 g 1 m 4

2.2 (a) (b) (c)

1 m 1 h 760 mi = 340 m / s h 0.0006214 mi 3600 s 921 kg 2.20462 lb m m3 1 kg 1 m3 = 57.5 lb m / ft 3 35.3145 ft 3 1.34 × 10 -3 hp = 119.93 hp ⇒ 120 hp 1 J/s

5.37 × 10 3 kJ 1 min 1000 J min 60 s 1 kJ

2.3 Assume that a golf ball occupies the space equivalent to a 2 in × 2 in × 2 in cube. For a classroom with dimensions 40 ft × 40 ft × 15 ft : 40 × 40 × 15 ft 3 (12) 3 in 3 1 ball n balls = . = 518 × 10 6 ? 5 million balls ft 3 2 3 in 3 The estimate could vary by an order of magnitude or more, depending on the assumptions made. 2.4 4.3 light yr 365 d 24 h
1 yr 1d 3600 s 1.86 × 10 5 mi 1 h 1 s 3.2808 ft 0.0006214 mi 1 step = 7 × 1016 steps 2 ft

2.5 Distance from the earth to the moo


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